2x^2-17x-240=0

Solution for 2x^2-17x-240=0 equation:

2x^2-17x-240=0

a = 2; b = -17; c = -240;
Δ = b2-4ac
Δ = -172-4·2·(-240)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-47}{2*2}=\frac{-30}{4}
=-7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+47}{2*2}=\frac{64}{4}
=16
$